April
2005, Issue 177
Test Your
EQ
|
Answer
5The
analysis is pretty straightforward, if you break it down
into components that we’ll assume are independent of each
other. There are two components to consider: your horizontal
cross-section (the view looking down on the top of your
head) and your vertical cross-section (the view looking
at your front).
Your
horizontal cross-section intercepts raindrops at a constant
rate for as long as you are out, regardless of your (horizontal)
speed. Your vertical cross-section intercepts raindrops
that are in a certain volume of air at the moment you
start moving. If you were to move infinitely fast, that
volume would be horizontal and would extend from your
starting point to the shelter. If you were to move somewhat
more slowly, the volume would be skewed upward from your
starting point at an angle that would depend on your speed
relative to the rain’s downward velocity.
Now,
the interesting thing is that this skewed shape has exactly
the same volume as the horizontal one! (This follows from
the area of a parallelogram, which is simply base × height.)
This means that the amount of rain you catch on your front
is only a function of your distance to the shelter and
is completely independent of your speed. Therefore, your
total wetness is minimized by minimizing the wetness of
the horizontal cross-section, which is minimized by getting
to shelter as soon as possible or running as fast as you
can.
Contributor:
David Tweed